What is the Impulse and Average Force in a Collision between a Ball and Wall?

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Homework Help Overview

The problem involves a 300g ball colliding with a wall at a speed of 6.0 m/s and an angle of 30 degrees, then rebounding with the same speed and angle. The task is to determine the impulse on the ball from the wall and the average force on the wall from the ball, with the ball in contact with the wall for 10 ms.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculations for initial and final momentum, questioning arithmetic accuracy and the resulting impulse and average force values. There is a focus on the vector components of the velocities involved in the collision.

Discussion Status

Participants are actively engaging with the calculations, with some expressing uncertainty about their results. There is a collaborative effort to verify arithmetic and clarify the setup of the problem, but no consensus on the correctness of the final answers has been reached.

Contextual Notes

Some participants mention personal challenges affecting their ability to process the problem, which may influence the pace and clarity of the discussion.

Ready2GoXtr
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Homework Statement


A 300g ball with a speed v of 6.0m/s strikes a wall at an angle theta of 30 degrees and then rebounds with the same speed and angle. It is in contact with the wall for 10ms. In unit-vector notation, what are (a) the impulse on the ball from the wall and (b) the average force on the wall from the ball?

http://ready2goxtr.googlepages.com/problem936.jpg


Homework Equations


Pi = Pf

Delta (P) = I
P = mv
<v being a vector>

Favg = I / (delta T)


The Attempt at a Solution



m = .3kg v = 6m/s theta = 30 degrees t = 10ms = .01s

a) Pi = PF

Pi = .3kg(Vcos(-30) i + Vsin(-30) j) = .26 kg * m/s i - 3 kg * m/s j

Pf = .3kg(Vcos(30) i + Vsin(30) j) = .26 kg * m/s i + 3 kg * m/s j

I = Delta (P) I = PF - PI

PF - PI = 6 kg * m/s j


b) I = sqrt(a^2 + b^2)
6kg * m/s / .01s = 600 N



I know i did it wrong. And thank you ahead of time.
 
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Ready2GoXtr said:
Pi = .3kg(Vcos(-30) i + Vsin(-30) j) = .26 kg * m/s i - 3 kg * m/s j

Pf = .3kg(Vcos(30) i + Vsin(30) j) = .26 kg * m/s i + 3 kg * m/s j
Double check your arithmetic.
 
whats wrong with it? Sorry if I am a bit slow, all the chemotherapy i had last year sort of slowed me down i think.
 
Ready2GoXtr said:
whats wrong with it?
For example: .3*6*sin(30) = ?
 
Oh Duh me. 0.9 but still, I highly doubt that I = 1.8 kg * m/s J
 
well in that case I = 1.9 kg * m/s J and Favg = 180 N
 
Okay so that must be right answer then?
 
Sounds good to me. Express your answers using unit vectors.
 
Do i need to open up a new post for a new question?
 
  • #10
Ready2GoXtr said:
Do i need to open up a new post for a new question?
In general: If it's a new problem, use a new thread. If it's a followup question on the same problem, ask it here.
 

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