1. The problem statement, all variables and given/known data a 250 g ball with a speed v of 6.6 m/s strikes a wall at an angle θ (the angle between the wall and the path of motion) of 30° and then rebounds with the same speed and angle. It is in contact with the wall for 6 ms. What is the impulse on the ball from the wall? 2. Relevant equations J is the impulse J = mvfinal - mvinitial the change in momentum (P) = Jnet P = mv 3. The attempt at a solution First I broke the velocity vectors into components: 6.6m/s * cos(30) = 5.716m/s 6.6m/s * sin(30) = 3.3 m/s, so Vo = 3.3i + 5.716j (m/s) and Vfinal = 3.3i - 5.716j (m/s) and the momentum of each is the mass of the object * the velocity: (.25kg)Vo = Po = .825i + 1.428j (.25kg)vfinal = Pfinal = .825i - 1.428j so Jnet = Pfinal - Pinitial = (.825-.825) i + (-1.428 -1.428)j so Jnet = -2.856 in the j direction so the answer should be -2.856, but it is not (and it is not 2.856 either)... any help is appreciated. Thanks!