- #1
Amith2006
- 427
- 2
Sir,
The diameter of a metal ring is D and the coefficient of linear expansion is y. The temperature of the ring is increased by 1 degree Celsius. What is the increase in area of the ring?
I solved it the following way:
Coefficient of superficial expansion = 2y
Initial area of the ring(A) = [(pi)D^2]/4
Increase in diameter of the ring = Dy
Increase in area of the ring = A x (2y)
= [(pi)D^2]/4 x 2y
= [(pi)(D^2)y]/2
But the answer given in my book is 2(D^2)y. Please help. Here the symbol ^ stands for power.
The diameter of a metal ring is D and the coefficient of linear expansion is y. The temperature of the ring is increased by 1 degree Celsius. What is the increase in area of the ring?
I solved it the following way:
Coefficient of superficial expansion = 2y
Initial area of the ring(A) = [(pi)D^2]/4
Increase in diameter of the ring = Dy
Increase in area of the ring = A x (2y)
= [(pi)D^2]/4 x 2y
= [(pi)(D^2)y]/2
But the answer given in my book is 2(D^2)y. Please help. Here the symbol ^ stands for power.