What Is the Initial Speed of a Diver Jumping from a 10m Board?

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SUMMARY

The discussion focuses on calculating the initial speed of a diver jumping from a 10-meter diving board at a 30-degree angle above the horizontal. The diver reaches the water in 2 seconds, and the acceleration due to gravity is 9.81 m/s². The equations of motion used include v = vi + at, s = si + vit + 0.5(a)t², and v² = Vi² + 2a(s - s0). The challenge lies in determining the initial velocity and its components, particularly the vertical component.

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Matt1234
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Homework Statement




A diver jumps from a 10 m high diving board at an angle of 30 deg above horizontal. 2 seconds later the diver reaches water. What is the initial speed of the diver ?

Homework Equations


v = vi + at
s = si + vit +0.5(a)t^2
v^2= Vi^2 + 2 a (s-s0)


The Attempt at a Solution




I tried applying the above equations yet i can't seem to come up with the method. I know Acceleration is constant 9.81 m/s^2. But the initial velocity is throwing me off, i have also tried to break the velocity into components, but was unseccessful.
Thank you.
 
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Matt1234 said:
But the initial velocity is throwing me off, i have also tried to break the velocity into components, but was unseccessful.
Show what you've tried. Hint: If the initial velocity is 'v', what's the vertical component?
 
here is my attempt, I am sorry for the poor handwriting and poor quality scan. Thank you for your help.

[PLAIN]http://img24.imageshack.us/img24/7664/lastscanql.jpg
 
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