What Is the Initial Speed of the Bullet in a Bullet-Block Collision Problem?

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SUMMARY

The discussion focuses on calculating the initial speed of a bullet in a bullet-block collision problem, where a bullet of mass 0.0100 kg strikes a block of mass 5 kg and becomes embedded. The block-bullet system moves 6 m on a rough table with a coefficient of kinetic friction of 0.300. The key equations involved are the conservation of momentum and the work-energy principle, specifically m1v1 = (M+m)V2 - fkd. The solution requires establishing two equations to solve for the unknowns V2 and v1.

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Homework Statement


A bullet of mass 0.0100kg moving horizontally strikes a block of M=5kg and becomes embedded. If the block bullet move a distance of 6 m on a rough horizontal table. The coefficient of kinetic friction is 0.300. What is the speed of the bullet before striking the block ?


Homework Equations



m1v1= ( M+m) V2 - fkd (1)



The Attempt at a Solution



I got two unknowns and one equation. I do not have V2 and v1 so l am stuck.
 
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Nyasha said:

Homework Equations



m1v1= ( M+m) V2 - fkd (1)
This looks like some mix of momentum conservation and work. No good!

I got two unknowns and one equation. I do not have V2 and v1 so l am stuck.
Find two equations:
(1) Conservation of momentum for the collision.
(2) Energy/work applied after the collision.

Hint: Use equation 2 first.
 

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