What Is the Initial Velocity of a Ball Thrown Upwards from a Building?

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SUMMARY

The discussion focuses on calculating the initial velocity of a ball thrown upwards from a height of 20.0 meters, with a total descent time of 5.5 seconds. The formula used for this calculation is x = x₀ + v₀t + 1/2at², which is confirmed as appropriate for the problem. It is crucial to establish positive and negative directions before applying the formula to avoid errors in the calculation.

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petal5
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The question is as follows:

A man stands at the edge of the roof of a building 20.0m above the ground.He throws a ball vertically straight upwards(it just misses the edge of the building as it falls back down).If the total time taken for the ball to travel from his hand to the ground is 5.5seconds what is the initial velocity of the ball?

My question is,is it correct to use the following formula to solve the problem: x=xo + volt + 1/2at^2

Thanks!
 
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Yes, it is. However, do be careful when dealing with the directions. Define ur +ve and -ve directions first.
 
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