What is the Inner Product between Tensors in Cartesian System?

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SUMMARY

The discussion centers on calculating the inner product between a twice covariant tensor T represented by the matrix [1, 0, 2; 3, 4, 1; 1, 3, 4] and a first-order contravariant tensor A defined as A = e_1 + 2e_2 + 3e_3. The inner product is expressed as S = u^i v_i, where the superscript indicates contravariance and the subscript indicates covariance. The resultant tensor from this operation is determined to be a first-order tensor.

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Telemachus
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Hi there. I have this problem, which says: In the cartesian system the tensor T, twice covariant has as components the elements of the matrix:
[tex]\begin{bmatrix}{1}&{0}&{2}\\{3}&{4}&{1}\\{1}&{3}&{4}\end{bmatrix}[/tex]

If [tex]A=e_1+2e_2+3e_3[/tex] find the inner product between both tensors. Indicate the type and order of the resultant tensor.

Well, I don't know how to do this. Which type of tensor is A? I think that could help.
The inner product is defined for tensors of different kinds as:
[tex]S=u^iv_i[/tex]

The supraindex indicates contravariance and the subindex covariance.
 
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Hi Telemachus! :smile:

I think they're saying that A is first-order contravariant, so T.A will be TijAj :wink:

(btw, not what i'd call a dot product :frown:)
 
Why not?

Thank you Tim :)
 

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