What is the Integral of Sin(sqrt(t))?

[SplinterIon]

I'm drawing a blank as to how to approach this one. I've been looking over all trig identities and substitutions I could possibly make - but to no avail .

<br /> \int_{1}^{x^2} \sin{(\sqrt{t})} \ dt <br />

 

[MalleusScientiarum]

Try making a u-substitution for the square root of t.

 

[Orion1]

indefinite integral...


The closest identity that I could determine is:

identity:
\int u \sin u \; du = \sin u - u \cos u + C

\int \sin \sqrt{t} \; dt = 2 \left( \sin \sqrt{t} - \sqrt{t} \cos \sqrt{t} \right) + C

 

[HallsofIvy]

Try making a u-substitution for the square root of t.

Good try but it looks to me like that gives you
\int u^{\frac{1}{2}}sin u du which doesn't look any more hopeful.

I'd be willing to bet that this doesn't have an elementary anti-derivative.

 

[dextercioby]

Don't bet too much, Halls.

\sqrt{t}=u

implies t=u^{2} \ \mbox{and} \ dt= 2 u du

and the antiderivative becomes

\int 2 u \sin u \ du which can be easily tackled with the part integration method.

Daniel.

 

[HallsofIvy]

One of these days, I really have to learn algebra!