What is the interpretation of ∅-∅?

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The discussion centers on the interpretation of the expression ∅-∅, which logically represents the set of all x such that x is in the empty set and not in the empty set. Participants clarify that this results in the null set, as there are no elements that satisfy both conditions. The concept is further explained by relating set subtraction to the intersection of one set with the complement of another. Ultimately, the consensus is that ∅-∅ equals the empty set, reinforcing the idea that "nothing from nothing leaves nothing."
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What is ∅-∅ equal to?
Logically this is represented as the set containing all x such that x\in∅ and x\notin∅. I am confused on how to interpret this...I think the answer would just be the null set, but I am not sure. Could someone please clarify this?
 
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Think of the subtraction of sets as the intersection of the one with the complement of the other. That is ∅\cap ∅^{c}
 
There is no ##x## for which ##x \in \emptyset## and ##x \notin \emptyset##, so there are no elements in ##\emptyset - \emptyset##.
 
Makes me think of the song quite a few years back, "Nothin' from nothin' leaves nothin." - Billy Preston, 1975
 
Mark44 said:
Makes me think of the song quite a few years back, "Nothin' from nothin' leaves nothin." - Billy Preston, 1975
Great post, Mark !
 
SammyS said:
Great post, Mark !
:approve:
 
Aziza said:
What is ∅-∅ equal to?
Logically this is represented as the set containing all x such that x\in∅ and x\notin∅. I am confused on how to interpret this...I think the answer would just be the null set, but I am not sure. Could someone please clarify this?

That is exactly right. It may help to simplify that logical expression, because you can, for example, replace x \in \emptyset with a truth value.

Or maybe slightly reorganizing it to the fact that

x is in ∅-∅​

is synonymous with

x\in∅ and x\notin∅​
 

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