What is the largest value of Fw the cords can withstand?

  • Thread starter Thread starter badhorserides
  • Start date Start date
  • Tags Tags
    Value
Click For Summary

Homework Help Overview

The problem involves determining the maximum force (Fw) that cords can support, given that each cord can withstand a maximum tension of 80N. The discussion centers around the equilibrium of forces in both the x and y directions, with specific angles involved in the calculations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the equilibrium conditions and question the assumption that both tensions (Ft1 and Ft2) can be equal to 80N simultaneously. There is an exploration of how to express Fw in terms of one of the tensions.

Discussion Status

Some participants have provided guidance on how to approach the problem by suggesting that only one tension may reach the maximum value and that the other should be solved accordingly. There is an acknowledgment of potential mistakes in the initial assumptions regarding the tensions.

Contextual Notes

Participants note that assuming both tensions are equal could lead to a non-equilibrium condition in the x-direction, which is a critical point of discussion. There is also mention of the need to consider the maximum tension limits when solving for Fw.

badhorserides
Messages
2
Reaction score
0

Homework Statement



Cords can withstand a maximum tension of 80N. What is the largest value of Fw they can support?

Homework Equations



Ft1 and Ft2 are 80.

FsysX = Ft1 sin 60 + Ft2 sin 70, but x doesn't matter

Fsys Y = Ft1 cos 60 + Ft2 cos 70 - Fw

The Attempt at a Solution



80 cos 60 + 80 cos 70 - Fw
Fw= 40+ 27
Fw = 67, when it should be 55.
 

Attachments

  • Screen shot 2011-12-10 at 3.49.10 PM.png
    Screen shot 2011-12-10 at 3.49.10 PM.png
    3.2 KB · Views: 518
Physics news on Phys.org
badhorserides said:

Homework Statement



Cords can withstand a maximum tension of 80N. What is the largest value of Fw they can support?

Homework Equations



Ft1 and Ft2 are 80.

FsysX = Ft1 sin 60 + Ft2 sin 70, but x doesn't matter (It does matter.)

Fsys Y = Ft1 cos 60 + Ft2 cos 70 - Fw

The Attempt at a Solution



80 cos 60 + 80 cos 70 - Fw
Fw= 40+ 27
Fw = 67, when it should be 55.

It's a mistake for you to assume that both F1 and F2 are equal to 80 N. That will lead to a non-equilibrium condition in the x-direction.

Probably only one of them will be at the maximum value. You should be able to solve for Fw in terms of F1 or F2 .
 
SammyS said:
It's a mistake for you to assume that both F1 and F2 are equal to 80 N. That will lead to a non-equilibrium condition in the x-direction.

Probably only one of them will be at the maximum value. You should be able to solve for Fw in terms of F1 or F2 .


So I should say, for example, T1 is going to be equal to 80, solve for T2 in the X direction using that, then use those to solve for the weight.

I'll try it! Thank you!
 
Yes, you can try that. It may turn out that doing this gives you that T2 > 80 N, in which case you will need to assume that T2 = 80N.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 24 ·
Replies
24
Views
4K
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
15K
Replies
3
Views
5K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 34 ·
2
Replies
34
Views
4K
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
5K