The discussion focuses on calculating the maximum load a platform can withstand while floating on water, supported by a rectangular plastic tank. The tank has a height of 0.35m and a base area of 0.5m². The equilibrium state of the tank is reached when submerged to a height of 0.07m, with an oscillation amplitude of 0.05m. The maximum buoyant force is calculated using the formula (0.23)(0.5)(9.81)(1000) N, where 0.23m is the effective submerged height during oscillation.
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If we assume the amplitude of the oscillation is still 0.05m, yes. But the question does not make that clear. Why should the amplitude stay the same? With the extra load, the energy flux is greater for the same amplitude. If we were to add some mass, gently, when the tank is at the equilibrium position the amplitude would decrease. Add the right extra mass at the lowest position and it would stop oscillating entirely.foo9008 said:so , the max weight = (0.23)(0.5)(9.81)(1000) N ? is correct ?
do you mean we can only find the maximum mass hat the tank can support with assumption of no oscillation ?haruspex said:If we assume the amplitude of the oscillation is still 0.05m, yes. But the question does not make that clear. Why should the amplitude stay the same? With the extra load, the energy flux is greater for the same amplitude. If we were to add some mass, gently, when the tank is at the equilibrium position the amplitude would decrease. Add the right extra mass at the lowest position and it would stop oscillating entirely.
Low marks to the question setter.
can i find the maximum buoyant force by not considering the amplitude of the oscilllation of the platform when there is no extra load on it ? if so , the maximum buoyant force = (0.28)(0.5)(9810)N ?haruspex said:If we assume the amplitude of the oscillation is still 0.05m, yes. But the question does not make that clear. Why should the amplitude stay the same? With the extra load, the energy flux is greater for the same amplitude. If we were to add some mass, gently, when the tank is at the equilibrium position the amplitude would decrease. Add the right extra mass at the lowest position and it would stop oscillating entirely.
Low marks to the question setter.
assuming the oscillation is 0.05m when the platform is empty and fully loaded , is the maximum buoyant force = 0.23)(0.5)(9.81)(1000) N ?haruspex said:If we assume the amplitude of the oscillation is still 0.05m, yes. But the question does not make that clear. Why should the amplitude stay the same? With the extra load, the energy flux is greater for the same amplitude. If we were to add some mass, gently, when the tank is at the equilibrium position the amplitude would decrease. Add the right extra mass at the lowest position and it would stop oscillating entirely.
Low marks to the question setter.
Yes, I confirmed that in post #31. I think you will have to assume that.foo9008 said:assuming the oscillation is 0.05m when the platform is empty and fully loaded , is the maximum buoyant force = 0.23)(0.5)(9.81)(1000) N ?