What is the Limit of a Rational Function?

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SUMMARY

The discussion focuses on finding the limit of the rational function \(\lim_{x\rightarrow0} \frac{\frac{1}{x+2}-\frac{1}{2}}{x}\) using algebraic methods. The user attempted to simplify the expression by multiplying by \(\frac{x}{x}\), leading to an intermediate form of \(\frac{x}{x+2}-\frac{x}{2}\). The correct approach involves combining the fractions in the numerator and simplifying further to evaluate the limit as \(x\) approaches 0.

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  • Basic knowledge of L'Hôpital's Rule (optional for verification)
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Homework Statement


All the problem is asking me to do is find the limit. I have to do it algebraicly too which sucks. I can't figure out how to do it.
[tex]\lim_{x\rightarrow0} \frac{\frac{1}{x+2}-\frac{1}{2}}{x}[/tex]


Homework Equations



I am not sure really.

The Attempt at a Solution


One thing I have tried is to multiply by [tex]\frac {x}{x}[/tex]. Which gave me:
[tex]\lim_{x\rightarrow0} \frac{\frac{1}{x+2}-\frac{1}{2}}{x} \times \frac {x}{x}[/tex]

[tex]=\frac{\frac{1\times x}{x+2}-\frac{1\times x}{2}}{x\times x}[/tex]

[tex]= \frac{\frac{x}{x+2}-\frac{x}{2}}{x^{2}}[/tex]

[tex]=\frac{x}{x+2}\rightarrow \frac{x}{x}+\frac{x}{2} \rightarrow 1+\frac{x}{2}[/tex]

[tex]=\frac{1+\frac{x}{2}-\frac{x}{2}}{x^{2}}[/tex]

[tex]=\frac{1}{x^{2}}[/tex]

1) I am not sure of my algebra during this and
2) I don't know where to go from here should my algebra check out.

I have already tried to multiply by [tex]\frac{\sqrt{x}}{\sqrt{x}}[/tex] but it just seems to give me [tex]\frac{\sqrt{x}}{x}[/tex] which doesn't help. I am stuck help me please?
 
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Combine the two fractions in the numerator and then simplify the whole thing.
 
Thank you! :):):):):):):):)
 

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