What is the limit of (a^x - 1)/x as x approaches 0?

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Homework Help Overview

The discussion revolves around evaluating the limit of the expression (a^x - 1)/x as x approaches 0, specifically exploring why the limit equals log(a).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of L'Hospital's rule and its application to the limit. There is also mention of using the Maclaurin series for a^x as an alternative approach. Questions arise regarding the reasoning behind the limit's value and the possibility of solving it without L'Hospital's rule.

Discussion Status

The discussion is active, with participants exploring different methods to evaluate the limit. Some guidance has been offered regarding the use of derivatives and series expansion, but there is no explicit consensus on the preferred approach yet.

Contextual Notes

Participants are navigating assumptions about the limit and the mathematical tools available to them, such as L'Hospital's rule and series expansions, without resolving the underlying concepts fully.

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Homework Statement



lim x->0 ( (a^x - 1)/x )

Homework Equations



NA

The Attempt at a Solution



The professor told me that the answer to that limit is log(a), but why? I don't understand; can someone explain why?
 
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Do you know l'hopital's rule?
 
gb7nash said:
Do you know l'hopital's rule?


Yeah, I just figured it out. Take the derivative of both the numerator and the denominator and then it's easy from there...

Is there any way to do it without having to use L'Hospital's?
 
You could take the maclaurin series of a^x and plug it in for a^x. Once you do this, stuff cancels out and you'll obtain the same answer.
 

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