(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

## \lim x-0 \frac {xcosx-log(1+x)}{x^2}##

2. Relevant equations

##\frac{log(1+x)}{x}=1## ...(i)

3. The attempt at a solution

Using (i) we can write numerator as xcosx-x, cancelling x from denominator we have cosx-1/x, this is 0/0 form so we can use LHR which gives us -sinx/1 but this gives an incorrect value for the limit. Is there some technicality I'm overlooking about applying LHR?

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# Homework Help: Rules to apply L'Hospital on a limit

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