What is the Limit of the Tangent Function as x Approaches 0?

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SUMMARY

The limit of the tangent function as x approaches 0 is calculated as follows: \lim_{x \rightarrow 0} \frac {\tan x}{4x} = \frac{1}{4}. The discussion highlights the use of the limit property \lim_{x \rightarrow 0} \frac {\sin x}{x} = 1 as a foundational concept. Participants suggested avoiding L'Hôpital's rule and instead recommended using the definition of tangent and the limit of cosine. Ultimately, the correct manipulation leads to the conclusion that the limit evaluates to \frac{1}{4}.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with the tangent function and its properties
  • Knowledge of the limit property \lim_{x \rightarrow 0} \frac {\sin x}{x} = 1
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the definition and properties of the tangent function
  • Learn about limit properties in calculus
  • Explore Taylor series expansions for trigonometric functions
  • Review L'Hôpital's rule and its applications in calculus
USEFUL FOR

Students of calculus, particularly those struggling with limits and trigonometric functions, as well as educators seeking to clarify foundational concepts in calculus.

erik05
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Hello all. I missed a class in calculus so I didn't get the notes on this so if anyone could explain this question for me, it would be much appreciated.

\lim_{x \rightarrow 0} \frac {tanx}{4x}
= \frac {sinx}{cos4x} ?

Not really too sure if I manipulated the equation right. Any hints for the next step? Thanks.
 
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You can't do that!



Use l'hospital's rule.

\lim_{x \rightarrow 0} \frac {tanx}{4x} =\lim_{x \rightarrow 0} \frac {secxtanx}{4}
 
Sorry, I haven't learned l'hospital's rule yet and we're not suppose to use it for these questions.
 
expand tanx in taylor series, and do what you should do...
 
This is going to sound really pathetic but no, we haven't the taylor series either.
 
do you know the fact that
\lim_{x \rightarrow 0} \frac {sinx}{x} =1
if yes, you should start from here
 
I think Taylor series is taught way after l'Hôpital's rule,don't u think so?:rolleyes:

Daniel.
 
vincentchan said:
do you know the fact that
\lim_{x \rightarrow 0} \frac {sinx}{x} =1
if yes, you should start from here

That I do know.
 
What about "tangent's" definition...?And the limit of cosine as its argument goes to 0 ?

Daniel.
 
  • #10
erik05 said:
Hello all. I missed a class in calculus so I didn't get the notes on this so if anyone could explain this question for me, it would be much appreciated.

\lim_{x \rightarrow 0} \frac {tanx}{4x}
= \frac {sinx}{cos4x} ?

Not really too sure if I manipulated the equation right. Any hints for the next step? Thanks.

= 1/4*(sin[x]/x)*(sec[x])
 
  • #11
Ah...I got it. Thanks all.
 
  • #12
Limit Laminate...


Solution:
\boxed{\lim_{x \rightarrow 0} \frac {\tan x}{4x} = \frac{1}{4}}
[/color]
 
Last edited:
  • #13
How fancy that \boxed{...},too bad u don't know "\tan"...:rolleyes:

Daniel.

P.S.BTW,I've searched Mathworld and A & S,couln't find this tanx function... :bugeye:

P.P.S.Neither sinx,nor secxtanx,but i found \mbox{sinc}\ x...

P.P.P.S.You edited... :wink:
 
Last edited:

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