What Is the Linear Density of the String in a Standing Wave System?

Click For Summary

Homework Help Overview

The problem involves a string in a standing wave system, where the linear density of the string is to be determined based on the conditions of the system, including the mass of a block and the frequency of an oscillator. The setup includes nodes at both ends of the string and specific masses that create standing waves.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between mass, tension, and linear density, questioning how multiple masses can lead to standing waves and the implications for tension and density. There are attempts to relate frequency, wavelength, and tension through equations, while also considering the implications of the figure provided.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the equations to use, but there is no explicit consensus on how to resolve the quadratic equation that arises from the calculations.

Contextual Notes

Participants note potential confusion regarding the representation of the figure and its relevance to the actual problem, as well as the implications of having two different tensions affecting the linear density calculation.

Puchinita5
Messages
178
Reaction score
0

Homework Statement



In Fig. below, a string, tied to a sinusoidal oscillator at P and running over a support at Q, is stretched by a block of mass m.The separation L between P and Q is 2.30 m, and the frequency f of the oscillator is fixed at 142 Hz. The amplitude of the motion at P is small enough for that point to be considered a node. A node also exists at Q. A standing wave appears when the mass of the hanging block is 3503.5 g or 2574.0 g, but not for any intermediate mass. What is the linear density (in g/m) of the string?

Homework Equations


image: http://edugen.wiley.com/edugen/courses/crs1650/art/qb/qu/c16/pict_16_60.gif


The Attempt at a Solution


i'm confused because if two masses can make a standing wave, that would suggest two different tensions as well... and wouldn't this also suggest two different linear desnities?? i have no idea how to go about this problem...

if i were to guess, i would use f=v/wavelength to get v...but i don't know if I could assume the wavelength because the way the figure is drawn...because in the figure, the wavelength is obvious, but maybe the figure is just an example and not actually representative of what's happening...but if I do use the figure, then i can solve for v...then with v=(T/u)^.5...where T is tension and u is linear density, then i can solve for desnity, except I have two tensions to pick from...

other than that I'm lost...any help?
 
Physics news on Phys.org
If there are n loops in the standing wave, then L = n*λ/2. Or λ = 2L/n.
So v = f*λ = f*2L/n = ( T/μ )^0.5
Write two equations, one for T = 3503.5 g and other for 2574 g for the number of loops n and n + 1 respectively. Solve for n. Substitute it in one of the equations to find the linear density.
 
okay, solving for N, doesn't that give you two results for N because i ended up with a quadratic equation, how do you know which N to use?
 
oh wait nevermind, i did something silly
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
1K
  • · Replies 29 ·
Replies
29
Views
2K
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
13
Views
2K
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 15 ·
Replies
15
Views
2K