What is the <lz> Expectation Value for Given Wave Function?

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SUMMARY

The discussion focuses on calculating the expectation value of the angular momentum operator using the wave function \Psi = (Y11 + cY1-1)/(1 + c^2). The key equation involved is Ylm = \hbar m Ylm, where m represents the eigenvalue corresponding to the spherical harmonics Ylm. The notation indicates the expectation value, defined as = <\Psi| lz |\Psi>, which simplifies to a numerical value based on the linear superposition of eigenfunctions. Understanding the orthonormality of spherical harmonics is crucial for simplifying the resulting integral.

PREREQUISITES
  • Understanding of spherical harmonics (Ylm)
  • Familiarity with angular momentum operators in quantum mechanics
  • Knowledge of expectation values in quantum mechanics
  • Ability to perform integrals involving wave functions
NEXT STEPS
  • Study the properties of spherical harmonics and their orthonormality
  • Learn about angular momentum operators in quantum mechanics
  • Explore the concept of expectation values in quantum mechanics
  • Practice calculating integrals involving wave functions and operators
USEFUL FOR

Students and professionals in quantum mechanics, particularly those studying angular momentum, wave functions, and expectation values. This discussion is beneficial for anyone looking to deepen their understanding of these concepts in a quantum context.

Ant_of_Coloni
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Homework Statement


Find <lz> using [itex]\Psi[/itex], where [itex]\Psi[/itex]=(Y11+cY1-1)/(1+c^2)).

Ylm are spherical harmonics, and <lz> is the angular momentum operator in the z direction.


Homework Equations



<lz> Ylm = [STRIKE]h[/STRIKE]mYlm

The Attempt at a Solution



The brackets around <lz> are throwing me off. This isn't defined in my book, but am I just supposed to apply the above equation to [itex]\Psi[/itex]?

So <lz> = [STRIKE]h[/STRIKE]m(Y11+cY1-1)/(1+c^2)?

Also what would m be?
 
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Ant_of_Coloni said:

Homework Statement


Find <lz> using [itex]\Psi[/itex], where [itex]\Psi[/itex]=(Y11+cY1-1)/(1+c^2)).

Ylm are spherical harmonics, and <lz> is the angular momentum operator in the z direction.


Homework Equations



<lz> Ylm = [STRIKE]h[/STRIKE]mYlm

The Attempt at a Solution



The brackets around <lz> are throwing me off. This isn't defined in my book, but am I just supposed to apply the above equation to [itex]\Psi[/itex]?

So <lz> = [STRIKE]h[/STRIKE]m(Y11+cY1-1)/(1+c^2)?

Also what would m be?

The m is the eigenvalue of the lz operator for the spherical harmonic in question, i.e. the m in Ylm, i.e. +1 or -1 in your problem.

The <> notation surrounding an operator is implicitly the expectation value with respect to some given wavefunction:

<lz> = <[itex]\Psi[/itex]| lz |[itex]\Psi[/itex]>

I think your "relevant equation" should perhaps read

lz Ylm = [itex]\hbar[/itex]m Ylm

i.e. the operator is "naked" when it acts on the spherical harmonic. However, the equation you wrote is not exactly incorrect... it's just that <lz> is simply a number, not an operator, and the number is just [itex]\hbar[/itex]m provided [itex]\Psi[/itex] = Ylm. That's subtly different from the equation I wrote, which indicates that the operator acting the wavefunction gives you a multiple of the wavefunction. Does that make sense?


This is a pretty straightforward problem once you get the notation. The point is that the wave function is just a linear superposition of two eigenfunctions of the angular momentum operator, so the expectation is a linear function of the eigenvalues. But you have to do the algebra to get the right answer. And by "do the algebra" I mean to write down the expectation value, in which the wave function ψ shows up in both the bra and the ket form, in integral form, and make sure you understand how the orthonormality of the spherical harmonics makes the resulting integral "simple"...
 

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