What is the Magnetic Dipole Moment of a Spinning Spherical Shell?

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stunner5000pt
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Homework Statement


Find the magnetic dipole moment of a spherical shell of radiu R carrying a uniform surface charge sigma, set spinning at angular velocity omega.


Homework Equations


[tex]\vec{m} = \frac{1}{2} \int_{S} \vec{r'} \times \vec{K} (\vec{r'}) da'[/tex]

The Attempt at a Solution


So we got to figure out the surface charge density (since it is a spherical shell)

[tex]K = \sigma v[/tex]

and [tex]v = \omega times R[/tex]
this is where i am doubtful...
the angle between v and R varies from 0 to 2 pi

so this cross product is not unique...
or am i thinking about this the wrong way??

please help!
 
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You are right that the angle changes but v will always point in the correct direction. The changing angle ([tex]sin(\theta)[/tex]) accounts for the "azimuthal radius", that is, distance from the spin axis z to the shell measured parallel to the xy plane, that changes with polar angle. That distance is also the r you need to use in your integral.

BTW, polar angle only varies from 0 to [tex]\pi[/tex]