What is the magnitude of the contact force between the boxes?

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Homework Help Overview

The problem involves three boxes being pushed by a force of 7.50 N, with specific masses assigned to each box. The original poster is tasked with finding the contact forces between the boxes based on the applied force and their masses.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the acceleration and contact forces but initially overlooks the third box's mass. Some participants question how to incorporate all masses into the calculations.

Discussion Status

The discussion has seen attempts to clarify the approach to finding the acceleration and contact forces. Guidance has been offered regarding the application of Newton's 2nd law, and the original poster indicates progress in understanding the problem.

Contextual Notes

Participants are navigating the complexities of applying Newton's laws to a multi-body system, with some confusion regarding the inclusion of all masses in the calculations. There is an emphasis on ensuring the net force is correctly identified.

youxcrushxme
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I'm really confused about this problem -

As shown in Figure 5-22, a force of magnitude 7.50 N pushes three boxes with masses m1 = 1.30 kg, m2 = 3.30 kg, and m3 = 5.10 kg.

05-19alt.gif


(a) Find the magnitude of the contact force between boxes 1 and 2.
(b) Find the magnitude of the contact force between boxes 2 and 3.

So F=7.5N. First you need to find the acceleration right? So I got a=F/m and did 7.5/(1.3+3.3) for part a. That gave me 1.63. I multiplied that with 3.3 because that's the mass of the second box and got a contact force of 5.379N but it's telling me that it's not right. If anyone could help I'd really appreciate it
 
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youxcrushxme said:
So F=7.5N. First you need to find the acceleration right? So I got a=F/m and did 7.5/(1.3+3.3) for part a. That gave me 1.63.
What happened to the third mass?
 
I'm confused about how I work that in there...I was kind of doing the problem as if the third one wasn't there which is wrong. So I do 7.5/(1.3+3.3+5.1) to get a? And then once I have a how do I find the contact force?
 
You apply Newton's 2nd law: First to the entire 3-block system, to find a. Then to each mass separately, to find the contact forces. (Realize that the F in F = ma is the net force.)
 
Ahh, I figured it out, thanks
 

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