What is the magnitude of the electrostatic force between two point charges?

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SUMMARY

The magnitude of the electrostatic force between two point charges, Q1 = -9.4 C and Q2 = 3.6 C, separated by a distance of 4.8 m, is calculated using Coulomb's Law: F = (k(Q1*Q2))/r^2. Substituting the values, F = ((8.9876*10^9)(-9.4*3.6))/(4.8^2) yields approximately 1.32 * 10^10 N, which rounds to 1.3 * 10^10 N. The discussion highlights potential issues with online grading systems and the importance of significant figures in the final answer.

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therealkellys
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I've been working on the following problem but when I try my answer online, it keeps coming up as incorrect. A charge Q1=-9.4 C is 4.8 m from a charge Q2 = 3.6 C. What is the magnitude of the electrostatic force on Q1?

I'm pretty sure for this its just Coulomb's Law so:
F = (k(Q1*Q2))/r^2
F = ((8.9876*10^9)(-9.4*3.6))(4.8^2)
F ~ 1.32 * 10^10 N
Taking into account sig. figs, my final answer is 1.3*10^10 N. \

However, this keeps coming up as incorrect. Am I overlooking something? Thanks in advance for the help!
 
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therealkellys said:
I've been working on the following problem but when I try my answer online, it keeps coming up as incorrect. A charge Q1=-9.4 C is 4.8 m from a charge Q2 = 3.6 C. What is the magnitude of the electrostatic force on Q1?

I'm pretty sure for this its just Coulomb's Law so:
F = (k(Q1*Q2))/r^2
F = ((8.9876*10^9)(-9.4*3.6))(4.8^2)
F ~ 1.32 * 10^10 N
Taking into account sig. figs, my final answer is 1.3*10^10 N. \

However, this keeps coming up as incorrect. Am I overlooking something? Thanks in advance for the help!
Sounds right to me. Are you sure that the charges are given in Coulombs (and not microcoulombs or nanocoulombs)? Other than that, I can't see anything wrong.

Patrick
 
Yep, I just looked it over again and all charges are given in Coulomb's. I think I might email my professor to see if he can look it over. Perhaps its a bug in the online grading system? I'm fairly confident in my answer. Thanks for looking it over!
 
therealkellys said:
Yep, I just looked it over again and all charges are given in Coulomb's. I think I might email my professor to see if he can look it over. Perhaps its a bug in the online grading system? I'm fairly confident in my answer. Thanks for looking it over!
You are welcome. Yes, it might be a big. Or maybe the system is expecting an answer with 3 sig figs (even though the answer should really have only two sig figs). But your answer is correct.

Best luck!

Patrick
 

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