Problem in electrostatics: E-field near 2 point charges

In summary, the conversation discusses a homework problem involving charges and potential energy. The participants conclude that option a is incorrect due to unequal magnitudes of the charges, and options c and d are correct. They also mention difficulty in calculating the angle beta, but agree that it is not necessary to do so to disqualify option b. The problem is from an exam paper called NEST, conducted in India in 2016.
  • #1
ubergewehr273
142
5

Homework Statement


Refer the image.

Homework Equations


kq1q2/r^2 = F
Potential energy = kq1q1/r

The Attempt at a Solution


Obviously since both charges are unequal in magnitude option a is incorrect.
Calculating field at large distance r,
E = kq1/r^2 - kq2/r^2
= kq2/r^2
Also potential energy at q1 is lesser than near q2 for negative charge.
So options c,d are correct. However I don't understand how the angle beta can be calculated from the given information.
 

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  • #2
ubergewehr273 said:
However I don't understand how the angle beta can be calculated from the given information.
No need to calculate the angle to disqualify answer b.
 
  • #3
Doc Al said:
No need to calculate the angle to disqualify answer b.
I'm sorry but I don't quite understand. The answers given are b,c,d.
 
  • #4
Hmm. What book is this from?
 
  • #5
Doc Al said:
Hmm. What book is this from?
It's from an exam paper called NEST (National Entrance Screening Test) conducted in India. Its for the year 2016.
 
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