# Problem in electrostatics: E-field near 2 point charges

• ubergewehr273

Refer the image.

## Homework Equations

kq1q2/r^2 = F
Potential energy = kq1q1/r

## The Attempt at a Solution

Obviously since both charges are unequal in magnitude option a is incorrect.
Calculating field at large distance r,
E = kq1/r^2 - kq2/r^2
= kq2/r^2
Also potential energy at q1 is lesser than near q2 for negative charge.
So options c,d are correct. However I don't understand how the angle beta can be calculated from the given information.

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However I don't understand how the angle beta can be calculated from the given information.
No need to calculate the angle to disqualify answer b.

No need to calculate the angle to disqualify answer b.
I'm sorry but I don't quite understand. The answers given are b,c,d.

Hmm. What book is this from?

Hmm. What book is this from?
It's from an exam paper called NEST (National Entrance Screening Test) conducted in India. Its for the year 2016.