What is the magnitude of the force between the two charges?

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SUMMARY

The discussion focuses on calculating the magnitude of the force between two positive point charges that are 5.20 cm apart, given an electric potential energy of 71.0 microJoules. The relevant equations include the electric potential energy formula, U = kq1q2/r, and the force equation, F = qE. By manipulating these equations, participants concluded that the force can be derived from the potential energy and the distance between the charges.

PREREQUISITES
  • Understanding of Coulomb's Law and electric forces
  • Familiarity with electric potential energy concepts
  • Knowledge of the constants involved, such as Coulomb's constant (k)
  • Basic algebraic manipulation skills for solving equations
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  • Study the derivation of Coulomb's Law and its applications
  • Learn about electric potential energy in different configurations of charges
  • Explore the concept of electric fields and their relation to force
  • Investigate the role of dipoles in electric potential energy calculations
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Students in physics, particularly those studying electromagnetism, as well as educators looking for examples of force calculations between charged particles.

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Homework Statement



Two positive point charges are 5.20 cm apart.
If the electric potential energy is 71.0 microJoules, what is the magnitude of the force between the two charges?

Homework Equations



potential energy = U = qV
E=kq1q2/r^2
F=qE


The Attempt at a Solution



I've tried manipulating the equations and it does not work. Also, I'm not sure if this has something to do with dipoles
 
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The electric potential energy is given by:

[tex]U=\frac{kq_1q_2}{r}[/tex]

Since both charges are the same you can work them out from the potential energy given and then solve for the force.
 

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