What is the magnitude of the force between two charges using Coulomb's law?

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SUMMARY

The magnitude of the force between a +12 µC charge and a +2.7 mC charge, located 43 cm apart, can be calculated using Coulomb's law. The correct formula is F = k * q1 * q2 / r^2, where k is the Coulomb's constant (9 x 10^9 N m²/C²). After converting units to Coulombs and meters, the force is determined to be approximately 1.58 N. This calculation emphasizes the importance of using consistent units in physics equations.

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yoshiba
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Homework Statement


What is the magnitude of the force a +12 µC charge exerts on a +2.7 mC charge 43 cm away?


Homework Equations


I know I have to use the equation: F=kq1q2/r^2



The Attempt at a Solution


F=(9*10^9)(12)(2.7)/(43^2)
=157706868.6

?right?
 
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yoshiba said:

The Attempt at a Solution


F=(9*10^9)(12)(2.7)/(43^2)
=157706868.6
?right?

almost, attention to the unit system you are using...
 
so i would change mC to C and cm to m...
F=(9*10^9)(2.7*10^-6)(12*10^-6)/(.43^2)
=1.58 N

is this ok?
 
Last edited:

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