What is the magnitude of the magnetic field?

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SUMMARY

The magnitude of the magnetic field can be calculated using the formula B = torque / (n * i * A * sin(theta)). In this case, a rectangular coil with 37 turns, an area of 36 cm² (0.0036 m²), and a current of 0.8 A is subjected to a torque of 0.07 Nm at an angle of 18°. The correct calculation requires using sin(72°) instead of sin(18°) due to the relationship between the angle and the normal to the coil. The final result for the magnetic field strength is determined by substituting these values into the equation.

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What is the magnitude of the magnetic field??

Homework Statement



A small rectangular coil composed of 37 turns
of wire has an area of 36 cm2 and carries a
current of 0.8 A. When the plane of the coil
makes an angle of 18◦ with a uniform magnetic
field, the torque on the coil is 0.07 Nm.
What is the magnitude of the magnetic
field? Answer in units of T.

Homework Equations



Torque = n*i*A*B*sin(theta)
B= torque/(n*i*A*sin(theta))
n is the number of turns

The Attempt at a Solution



what i did is that i plugged all the given values .. but i keep get the wrong answer .. i don't know where is my mistake

thanx in advance
 
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Did you convert the area to m2?
 


theta is the angle made between the normal to the coil to the magnetic field. Think about it, if the coil is parallel to the magnetic field (theta = 0), the torque is maximum (the forces on the wires are directly opposite), as opposed to if you used sin 0 = 0, that is torque = 0. So you have to use sin 72 or cos 18 in the equation.

I don't even know if that's the problem, but I hope it helps.
 

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