What is the magnitude of the normal force of the table on the lower magnet?

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SUMMARY

The magnitude of the normal force of the table on the lower magnet is determined by analyzing the forces acting on the magnet. The relevant forces include the weight of the table and the weight of the lower magnet, both acting downward. The normal force arises from the contact repulsion between the table and the lower magnet, counteracting these downward forces. A free body diagram is essential for visualizing these interactions and confirming that the system is in equilibrium.

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  • Basic knowledge of forces and equilibrium
  • Concept of normal force in physics
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Homework Statement


What is the magnitude of the normal force of the table on the lower magnet?
(so there is a table with a magnet on top and below its surface)

Homework Equations



The Attempt at a Solution


So i was wondering if someone could help me figure out all of the forces acting on the magnet to find the normal force. So far:

- weight of the table (down)
- weight of the lower magnet (down)
and so i don't really understand what will oppose these forces.. the force from the magnet on the top of the table?

thanks :)
 
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Try drawing an overall diagram of the situation, then draw a free body diagram for the lower magnet. Is the table resting on a surface? Or is it suspended, being help in place by the two magnets?

In either case there should only be three forces you need to take into account, and two of them will be related to the third.

The normal force is the contact 'repulsion' between surfaces that prevents objects passing through each-other.
 

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