What is the magnitude of the uniform electric field

Click For Summary
SUMMARY

The magnitude of the uniform electric field required to stop electrons with a kinetic energy of 1.40 x 10-17 J over a distance of 13.0 cm is calculated to be 673 N/C. The discussion also addresses the time taken to stop the electrons and the acceleration experienced after stopping, but the correct answers for these parts were not provided. Key formulas referenced include W = F d = q E d = K.E. and F = m a = q E.

PREREQUISITES
  • Understanding of kinetic energy and its relation to electric fields
  • Familiarity with the formula W = F d = q E d = K.E.
  • Knowledge of Newton's second law, F = m a = q E
  • Basic concepts of particle motion and acceleration
NEXT STEPS
  • Research the derivation of electric field strength from kinetic energy
  • Study the relationship between force, mass, and acceleration in electric fields
  • Learn about the motion of charged particles in electric fields
  • Explore the concepts of work and energy in the context of electric forces
USEFUL FOR

Physics students, electrical engineers, and anyone interested in the dynamics of charged particles in electric fields.

salome
Messages
1
Reaction score
0
Each of the electrons in a particle beam has a kinetic energy of 1.40 10-17 J.
(a) What is the magnitude of the uniform electric field (pointing in the direction of the electrons' movement) that will stop these electrons in a distance of 13.0 cm?
correct check mark N/C

(a) was 673 N

(b) How long will it take to stop the electrons?
wrong check mark
Your answer differs from the correct answer by 10% to 100%. ns
(c) After the electrons stop, the electric field will act on them, causing the electrons to accelerate in a direction correct check mark at what rate?
wrong check mark
Your answer differs from the correct answer by orders of magnitude. m/s2 i was not able to find the answers for par b and c and help would be appreciated! thanks
 
Physics news on Phys.org
a : W = F d = q E d = K.E.
b : F = m a = q E && x = (1/2) a t^2
c : see above
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 23 ·
Replies
23
Views
4K