What Is the Magnitude of Vector A?

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The magnitude of vector A can be determined through vector addition principles. Given that vector B has a magnitude of 9.0 m and the resultant vector is directed along the y-axis with a magnitude of 6 times that of vector A, the relationship can be expressed as A + 9 = 6A. By solving this equation, the magnitude of vector A is calculated to be 1.5 m. This conclusion is reached by recognizing the necessity of considering both magnitude and direction in vector addition.

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Vector A, which is directed along an x axis, is to be added to vector B, which has a magnitude of 9.0 m. The sum is a third vector that is directed along the y axis, with a magnitude that is 6 times that of A. What is the magnitude of A? (Enter your answer to 4 significant figures.)

So I know that vector B is 9 m. With the given information, I made the assumption that vector A is Vector A + 9. And finally, the third vector, the sum, would be 6(vector A). Am I on the right train of thought with the problem? To solve for the missing variables, can I use a + b = c?
 
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Vectors have both magnitude and direction. You can't just add the magnitudes and ignore the directions. You will have to break up the vectors into x and y-components and add them. I suggest possibly drawing a picture.
 

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