# What is the mangitude field inside the inner solenoid?

• jersey
In summary, the problem involves calculating the magnetic field inside a solenoid with 4000 turns of wire and another solenoid inside it with 2500 turns of wire. The equation used is B=uIN/l, where B is the magnetic field, u is the permeability, I is the current, N is the number of turns of wire, and l is the length of the solenoid. The calculation should take into account the turn density and ensure units are consistent.
jersey

## Homework Statement

1. Homework Statement

A 20cm long solenoid has 4000 turns of wire. Insiude this solenoid is a second on, also 20cmlong but with 2500 turns of wire. If a 2.5 A current flows in each solenoid in the same directon, what is the magnetic field inside the inner solenoid?

2. Homework Equations

See below.

3. The Attempt at a Solution

magnetic field = permeability x turn density x current

For a solenoid of length L 20cm with N = 2500 turns , the turn density is n= N/L = 125 turns/ m.
I=2.5 ampres.

B =0.07853981633974483 Tesla

Is this correct?

Does the Does the fact that it is one inside the other affect my calculations?
]

the field inside the inner coil is simply the sum of the field due to the inner coil plus the field due to the outer coil

So I have:
magnetic field = permeability x turn density x current

For a solenoid of length L 20cm with N = 2500 turns , the turn density is n= N/L = 125 turns/ m.
I=2.5 ampres.

B =0.07853981633974483 Tesla

+

magnetic field = permeability x turn density x current

For a solenoid of length L 20cm with N = 4000 turns , the turn density is n= N/L = 200 turns/ m.
I=2.5 ampres.

B = Tesla

argh! what am i not getting?

mixing cm with m

.20 should be used not 20.

What about my second equation, can you help me substitute in?

Can anyone help me with this question?

B=uIN/l

N=turns of wire
l= length if solenoid
u= 4(pi)(10^-7Tm/A)

## 1. What is a solenoid and what is its purpose?

A solenoid is a coil of wire that is used to create a magnetic field. Its purpose is to convert electrical energy into mechanical energy, such as in motors, or to convert mechanical energy into electrical energy, such as in generators.

## 2. How does a solenoid work?

A solenoid works by running an electric current through the coil of wire, which creates a magnetic field. The strength of the magnetic field depends on the number of turns in the coil and the amount of current flowing through it.

## 3. What is the magnitude field inside a solenoid?

The magnitude field inside a solenoid is dependent on the number of turns in the coil, the current flowing through the coil, and the material of the core. It can be calculated using the formula B = μ0 * n * I, where B is the magnetic field, μ0 is the permeability of free space, n is the number of turns, and I is the current.

## 4. How does the magnitude field change inside the inner solenoid?

The magnitude field inside the inner solenoid changes depending on the distance from the center of the solenoid. The closer to the center, the stronger the magnetic field will be. As you move away from the center, the magnetic field will decrease in strength.

## 5. How is the magnitude field inside a solenoid measured?

The magnitude field inside a solenoid can be measured using a device called a teslameter, which measures the strength of a magnetic field. The teslameter is placed at different points inside the solenoid to get an accurate reading of the magnetic field strength at those points.

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