What is the Mass of the Block in a Ballistic Pendulum Collision?

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Homework Statement



A 12g bullet is fired at 1600m/s into a wooden block of a ballistic pendulum, causing it to swing back, raising up 1.40m vertically. Find mass of the block



Homework Equations



N/a

The Attempt at a Solution



bullet momentum= 12g*1600m/s=19.2kgm/s
 
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johndoe14 said:

Homework Statement



A 12g bullet is fired at 1600m/s into a wooden block of a ballistic pendulum, causing it to swing back, raising up 1.40m vertically. Find mass of the block

Homework Equations



N/a

The Attempt at a Solution



bullet momentum= 12g*1600m/s=19.2kgm/s

Welcome to PF.

What's happened to the kinetic energy of the bullet? Think maybe it got translated into the block?
 
am i correct by saying that the block has a kinetic energy of____ due to the bullet

ke= .5*.012kg*1600m/s^2
= 15360kgm/s^2
 
johndoe14 said:
am i correct by saying that the block has a kinetic energy of____ due to the bullet

ke= .5*.012kg*1600m/s^2
= 15360kgm/s^2

Not quite. It's V2

If it absorbed that much KE and the block and bullet was raised by 1.4m then ...
 
do we assume that when the bullet collides with the block the block has the same velocity as the bullet?