What is the speed of the bullet in a ballistic pendulum collision?

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SUMMARY

The discussion focuses on calculating the speed of a bullet in a ballistic pendulum collision involving a 16g bullet and a 1.5kg bob. The correct approach involves using the conservation of momentum and energy principles. The participant initially calculated the final velocity incorrectly due to an arithmetic error in mass substitution. The correct speed of the bullet, after recalculating with the proper mass, is determined to be 346.2 m/s.

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Homework Statement



A 16g bullet is fired into the bob of a ballistic pendulum of mass 1.5kg When the bob is at its maximum height, the strings make an angle of 60 degree with the vertical. The length of the pendulum is 2.3 m. Find the speed of the bullet.

Homework Equations



pi=pf

The Attempt at a Solution



So I think it is an inelastic collision so vf = (mbullet*vbullet) / (mbullet+mblock)

After collision:

(1/2)*(mbullet+mblock)vf2 = (mbullet+mblock)*g*h

h=2.3-2.3*cos60=1.15m

then I solved for vf2=2*9.981*1.15=22.563

the I substitute into the first formula ( I actually squared both sides to use vf^2) to find vbullet= 346.2 m/s. However it is wrong. Where did I do wrong ??
 
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Your method looks perfect. Check your arithmetic in your last step.
 
Cool. I found out that I got the wrong mass for the last computation, I put in 1.15 instead of 1.5
 

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