What is the Mass of the Block in a Ballistic Pendulum Collision?

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A 12g bullet traveling at 1600m/s impacts a wooden block in a ballistic pendulum, causing it to swing and rise 1.40m. The bullet's momentum is calculated as 19.2 kgm/s. Participants discuss the conversion of the bullet's kinetic energy into the block's motion, questioning whether the block assumes the bullet's velocity upon impact. The kinetic energy of the bullet is calculated but corrected to reflect the proper formula. The discussion centers on determining the mass of the block based on the energy transfer during the collision.
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Homework Statement



A 12g bullet is fired at 1600m/s into a wooden block of a ballistic pendulum, causing it to swing back, raising up 1.40m vertically. Find mass of the block



Homework Equations



N/a

The Attempt at a Solution



bullet momentum= 12g*1600m/s=19.2kgm/s
 
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johndoe14 said:

Homework Statement



A 12g bullet is fired at 1600m/s into a wooden block of a ballistic pendulum, causing it to swing back, raising up 1.40m vertically. Find mass of the block

Homework Equations



N/a

The Attempt at a Solution



bullet momentum= 12g*1600m/s=19.2kgm/s

Welcome to PF.

What's happened to the kinetic energy of the bullet? Think maybe it got translated into the block?
 
am i correct by saying that the block has a kinetic energy of____ due to the bullet

ke= .5*.012kg*1600m/s^2
= 15360kgm/s^2
 
johndoe14 said:
am i correct by saying that the block has a kinetic energy of____ due to the bullet

ke= .5*.012kg*1600m/s^2
= 15360kgm/s^2

Not quite. It's V2

If it absorbed that much KE and the block and bullet was raised by 1.4m then ...
 
do we assume that when the bullet collides with the block the block has the same velocity as the bullet?
 

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