What is the Mass of the Block in a Ballistic Pendulum Collision?

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Homework Help Overview

The problem involves a ballistic pendulum scenario where a bullet collides with a block, causing it to swing upward. Participants are tasked with finding the mass of the block based on the given parameters of the bullet's mass and velocity, as well as the height the block rises after the collision.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the momentum of the bullet and its conversion into kinetic energy for the block. Questions arise regarding the relationship between the bullet's kinetic energy and the block's motion after the collision. There is also inquiry into whether the block moves with the same velocity as the bullet immediately after the collision.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the collision and energy transfer. Some guidance has been offered regarding the kinetic energy of the bullet and its implications for the block's motion, but no consensus has been reached on the correct approach to find the mass of the block.

Contextual Notes

Participants are working under the constraints of the problem statement, which does not provide explicit equations or methods for solving the mass of the block. There is an emphasis on understanding the energy transformations involved in the collision.

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Homework Statement



A 12g bullet is fired at 1600m/s into a wooden block of a ballistic pendulum, causing it to swing back, raising up 1.40m vertically. Find mass of the block



Homework Equations



N/a

The Attempt at a Solution



bullet momentum= 12g*1600m/s=19.2kgm/s
 
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johndoe14 said:

Homework Statement



A 12g bullet is fired at 1600m/s into a wooden block of a ballistic pendulum, causing it to swing back, raising up 1.40m vertically. Find mass of the block

Homework Equations



N/a

The Attempt at a Solution



bullet momentum= 12g*1600m/s=19.2kgm/s

Welcome to PF.

What's happened to the kinetic energy of the bullet? Think maybe it got translated into the block?
 
am i correct by saying that the block has a kinetic energy of____ due to the bullet

ke= .5*.012kg*1600m/s^2
= 15360kgm/s^2
 
johndoe14 said:
am i correct by saying that the block has a kinetic energy of____ due to the bullet

ke= .5*.012kg*1600m/s^2
= 15360kgm/s^2

Not quite. It's V2

If it absorbed that much KE and the block and bullet was raised by 1.4m then ...
 
do we assume that when the bullet collides with the block the block has the same velocity as the bullet?
 

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