What Is the Mass of the Second Ice Skater?

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SUMMARY

The discussion focuses on calculating the mass of the second ice skater using the principle of conservation of momentum. The first skater, weighing 60 kg, achieves a velocity of 0.61 m/s, while the second skater reaches a velocity of 0.8 m/s. The correct formula to apply is m1v1 = m2v2, which leads to the conclusion that the mass of the second skater is approximately 48 kg, correcting the initial miscalculation that incorrectly squared the velocities.

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Homework Statement



Two ice skaters stand at rest in the center of an ice rink. When they push off one another, the 60 kg skater acquires a speed of .61 m/s. If the speed of the other skater is .8m/s what is this skater's mass?

Homework Equations



explosion- pi=pf

The Attempt at a Solution



1/2m1v1^2=m2v2^2
1/2(60)(.61^2)=m2(.8^2)
11.16=m2(.64)
m2=17.43 but it said this was wrong

but then i got a really big number which doesn't seem right
 
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Recheck your formulas. What's the formula for the momentum of a moving body?
 
p=mv?
 
eagles12 said:
p=mv?
Is that a guess?
 
so do i do m1v1=m2v2 instead of squaring the velocities
 
got it! thanks
 
yes, that's right man. Its simply conservation of momentum.
 
There is NO "conservation of energy" (which is what you were trying to use first) because the "explosion" (push) adds energy to the system.
 

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