What is the max kinetic energy of photoelectrons from monochromatic beam?

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Homework Help Overview

The problem involves determining the maximum kinetic energy of photoelectrons emitted from a metal surface when exposed to a monochromatic light beam. The electric field of the beam becomes zero 1.2 x 1015 times per second, and the work function of the metal is given as 2.0 eV.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the frequency of the light and the given information, with some suggesting that the frequency could be 1.2 x 1015 Hz. There is also a mention of the need to convert the work function from eV to Joules before applying it in calculations.

Discussion Status

The discussion is ongoing, with participants exploring the interpretation of the frequency and its implications for the problem. Some guidance has been offered regarding the conversion of units and the correct formulation of the kinetic energy equation.

Contextual Notes

There is a focus on understanding the relationship between the frequency of the light and the behavior of the sine function, particularly how many times it crosses zero in a given period. This aspect is being clarified among participants.

utkarshakash
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Homework Statement


The electric field associated with a monochromatic beam becomes zero 1.2*10^15 times per second. Find the max kinetic energy of the photoelectrons when this light falls on a metal surface whose work function is 2.0 eV.

Homework Equations



The Attempt at a Solution


K(max)=hv-W where W=work function.
I have to find frequency from the given information which I don't know. But I guess it should be 1.2*10^15. Not sure about that.
 
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utkarshakash said:

Homework Statement


The electric field associated with a monochromatic beam becomes zero 1.2*10^15 times per second. Find the max kinetic energy of the photoelectrons when this light falls on a metal surface whose work function is 2.0 eV.

Homework Equations



The Attempt at a Solution


K(max)=hv-W where W=work function.
I have to find frequency from the given information which I don't know. But I guess it should be 1.2*10^15. Not sure about that.

I believe your interpretation that ##f = 1.2 \times 10^{15} Hz## would be the case.

Convert your work function into Joules before you use it.

Your equation also seems to be a bit off, it should read:

##E_k = hf - W##
 
Think about a sine function (or even better draw it).
How many times does it go through zero in a period?
It is easier to see if you take a period from a maximum to the next maximum in the sine wave.
 
nasu said:
Think about a sine function (or even better draw it).
How many times does it go through zero in a period?
It is easier to see if you take a period from a maximum to the next maximum in the sine wave.

I got that. Thanks!
 
Then what is the frequency of the light, in the problem?
Or you solved the question already?
 
nasu said:
Then what is the frequency of the light, in the problem?
Or you solved the question already?

I solved that.
 

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