What is the maximum angular speed for optimal mixing in a cement mixer?

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Homework Help Overview

The problem involves determining the maximum angular speed for optimal mixing in a cement mixer, where materials must not stick to the drum's wall. The context includes a rotating drum with specific dimensions and the effects of gravitational and normal forces on the mixing process.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between angular speed and the forces acting on the materials, including gravitational and normal forces. There is an exploration of the conditions under which the materials will fall from the top of the drum.

Discussion Status

Some participants have offered insights into the forces at play, questioning the assumptions about velocity and the conditions for mixing. Multiple interpretations of the forces involved are being explored, particularly regarding the role of centripetal force.

Contextual Notes

The discussion includes assumptions about the setup of the problem, such as the horizontal axis of rotation and the specific radius of the drum. There may be constraints related to the definitions of forces and their interactions that are still under consideration.

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Homework Statement


In a cement mixer, cement, gravel, and water are mixed by tumbling in a slowly rotating drum. If the drum spins too fast, the materials stick to the wall instead of mixing. Assume the axis of rotation is horizontal. Calculate the maximum angular speed for which the materials will mix. Express the answer as the number of revolutions per minute. Radius = 0.68 m.


Homework Equations





The Attempt at a Solution


I have tried using angular speed = v/r = theta/t . I assumed that t was equal to 1 minute and the angle was 2*pi. However, this did not work.
 
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The maximum angular velocity for which the material still mixes is when the material just falls down when it reaches the "top", maximum height, of the rotating drum. Which force makes the material fall? When the material just about sticks to the drum which force is equal to the mystery force that makes the material fall?
 
Okay, so I know that the force which pulls the mixture down is the gravitational force. I believe that the force which is the mystery force is the normal force. Thus, making g+N=0. I just before the mixture falls it would have a velocity of 0 or would it be the velocity the mixture is moving in based on the rev?
 
No the total velocity does not have to be 0 for the mixture to fall. Hint, centripetal force.
 

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