What is the maximum charge that can be put on a charged aluminum sphere?

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The maximum charge that can be placed on a charged aluminum sphere is significantly limited by the dielectric breakdown of air, which occurs at approximately 1 MV/m. To safely hold a charge of 8 Coulombs, the sphere would need a radius of 268 meters, making it impractical. A van der Graaff generator could theoretically charge the sphere, but the immense size required to prevent air breakdown renders the concept unfeasible. For smaller spheres, such as one the size of a basketball, the maximum charge would be considerably less than 8 Coulombs due to these constraints.

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Frogmansailor
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I am doing some conceptual design, and was hoping to be able to get some answers here before I devote too much time to this.

I would like to be able to charge a piece of aluminum so that it holds a charge (negative) of 8 Coulombs. I was hoping to achieve this with something similar to a van der graaf generator, which would charge a spherical piece of aluminum which is encased in a strong insulator so that the charge is safely contained.

So my questions are:

How big would this piece of aluminum have to be?
Would a van der graaf type generator work for this application?
How fast would this conductor bleed it's charge?
What insulator would best reduce this loss of charge?

Thanks in advance
Dave
 
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It's not going to happen. The field at the surface of a sphere is Q/(4*pi*epsilon_0*R^2), and air breaks down at a field strength of about 1 MV/m. To put 8 Coulombs on the sphere, you'd then need a sphere of a radius of 268 m to prevent the air around it from breaking down. 8 Coulombs is a lot of charge.
 
Well the dielectric breakdown of air being so low is the reason I want to surround it with a better insulator, so that isn't accurate.

I realize 8 C is a ton of charge, I was just hopeful I guess. What would the maximum charge that one could put on a sphere about the size of a basketball then?
 

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