What Is the Maximum Height Reached by a Falling Brick?

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SUMMARY

The maximum height reached by a falling brick, when dropped from a crane at a velocity of 5 m/s from a height of 6 meters, is calculated using kinematic equations. The brick's initial velocity upon separation is 5 m/s, and it falls under the influence of gravity. The brick will ascend briefly before descending, reaching a peak height of approximately 6.64 meters above the ground. This is determined by calculating the additional height gained after separation due to its initial velocity.

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  • Kinematic equations of motion
  • Understanding of gravitational acceleration (9.81 m/s²)
  • Basic physics concepts related to free fall
  • Velocity and height relationship in projectile motion
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A load of bricks is being lifted by a crane at a velocity of 5 m/s when one brick falls off 6m above the ground. What is the greatest height the brick reaches above the ground?

How do you solve it?

The attempt at a solution
Since it fell of 6 meters above the ground, the greatest height it reached was 6 meters.

But I'm not sure. Am I missing something?
 
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What velocity did the brick have just before it separated?
 

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