A golfer faces an approach shot from the fairway to an elevated green 6 metres above where she stands. She uses a pitching wedge with a loft of 70 degress and the ball leaves her club traveling at 35 m/s.(adsbygoogle = window.adsbygoogle || []).push({});

What is the maximum height the ball reaches above the level from which it was hit?

What I did:

vf^2=vi^2+2ad

0=(35sin70)^2+(2*-9.8)d

d=55 m

i was just wondering if i have to take the 6 metres into account?

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# Homework Help: What is the maximum height the ball reaches

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