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A golfer faces an approach shot from the fairway to an elevated green 6 metres above where she stands. She uses a pitching wedge with a loft of 70 degress and the ball leaves her club traveling at 35 m/s.
What is the maximum height the ball reaches above the level from which it was hit?
What I did:
vf^2=vi^2+2ad
0=(35sin70)^2+(2*-9.8)d
d=55 m
i was just wondering if i have to take the 6 metres into account?
What is the maximum height the ball reaches above the level from which it was hit?
What I did:
vf^2=vi^2+2ad
0=(35sin70)^2+(2*-9.8)d
d=55 m
i was just wondering if i have to take the 6 metres into account?