What is the maximum height the ball reaches

In summary, a golfer uses a pitching wedge with a loft of 70 degrees and a ball speed of 35 m/s to hit an approach shot from the fairway to an elevated green 6 metres above her. To find the maximum height the ball reaches above its initial level, the equation vf^2=vi^2+2ad is used, resulting in a maximum height of 55m. The 6-metre elevation does not need to be taken into account as the question only asks for the maximum height above the initial level.
  • #1
chukie
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A golfer faces an approach shot from the fairway to an elevated green 6 metres above where she stands. She uses a pitching wedge with a loft of 70 degress and the ball leaves her club traveling at 35 m/s.
What is the maximum height the ball reaches above the level from which it was hit?


What I did:
vf^2=vi^2+2ad
0=(35sin70)^2+(2*-9.8)d
d=55 m

i was just wondering if i have to take the 6 metres into account?
 
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  • #2


chukie said:
A golfer faces an approach shot from the fairway to an elevated green 6 metres above where she stands. She uses a pitching wedge with a loft of 70 degress and the ball leaves her club traveling at 35 m/s.
What is the maximum height the ball reaches above the level from which it was hit?


What I did:
vf^2=vi^2+2ad
0=(35sin70)^2+(2*-9.8)d
d=55 m

i was just wondering if i have to take the 6 metres into account?
No, since the question asked:
chukie said:
What is the maximum height the ball reaches above the level from which it was hit?
There is no need to take into account the initial height. However, if the question were to inquire about the ball landing then you would need to taking into account the additional 6m.
 
  • #3


thanks =)
 

1. What is the maximum height the ball reaches?

The maximum height the ball reaches is determined by multiple factors, including the initial velocity of the ball, the angle at which it is thrown, and the force of gravity. It can be calculated using the equation: h = (v2sin2θ)/2g, where h is the maximum height, v is the initial velocity, θ is the angle, and g is the acceleration due to gravity.

2. How do you calculate the maximum height of a ball?

To calculate the maximum height of a ball, you can use the formula: h = (v2sin2θ)/2g. First, determine the initial velocity of the ball and the angle at which it is thrown. Then, plug these values into the formula along with the acceleration due to gravity, which is typically 9.8 m/s2. The result will be the maximum height the ball reaches.

3. Does the mass of the ball affect its maximum height?

Yes, the mass of the ball does affect its maximum height. According to the equation h = (v2sin2θ)/2g, the mass of the ball is directly proportional to the maximum height. This means that a heavier ball will reach a higher maximum height compared to a lighter ball, assuming all other factors remain constant.

4. How does air resistance impact the maximum height of a ball?

Air resistance can have a significant impact on the maximum height of a ball. As the ball travels through the air, it experiences air resistance which acts in the opposite direction of its motion. This means that the ball will lose some of its initial velocity and therefore not reach as high of a maximum height as it would without air resistance. The extent to which air resistance affects the maximum height depends on the speed, size, and shape of the ball, as well as the density of the air.

5. Can the maximum height of a ball be greater than its initial height?

Yes, the maximum height of a ball can be greater than its initial height. This can occur when the ball is thrown at an angle, causing it to travel upwards before falling back to its initial height. However, without any external factors such as air resistance, the maximum height of the ball will always be equal to or less than its initial height.

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