MHB What is the Maximum Norm Proof for Matrix A?

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The discussion revolves around proving that for a matrix A in R^n×n, the infinity norm ||A||∞ equals the maximum of the sum of absolute values of its rows. Participants suggest starting with the p-norm and taking the limit as p approaches infinity. There is some confusion regarding the definition of the infinity norm, with clarification that for vectors, it is the maximum absolute value of the components. A recommended approach involves using the equivalent definition of the infinity norm and demonstrating both the upper and lower bounds through specific vector choices. The conversation emphasizes the importance of understanding the relationship between matrix norms and their definitions.
Amer
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Prove that for

$A \in \mathbb{R}^{n\times n} $
||A||_{\infty} = \text{max}_{i=1,...,n} \sum_{j=1}^n |a_{ij} |

I know that
$||A||_{\infty} = \text{max} \dfrac{||Ax||_{\infty} }{||x||_{\infty}} $

such that $x \in \mathbb{R}^n$

any hints
 
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Amer said:
Prove that for

$A \in \mathbb{R}^{n\times n} $
||A||_{\infty} = \text{max}_{i=1,...,n} \sum_{j=1}^n |a_{ij} |

I know that
$||A||_{\infty} = \text{max} \dfrac{||Ax||_{\infty} }{||x||_{\infty}} $

such that $x \in \mathbb{R}^n$

any hints

I believe you can start with $||A||_p$ the p norm and take the limit as $p\to\infty$ to prove the problem.
Isn't the infinity norm just the max of $|a_i|$ not the sum of them?
 
dwsmith said:
I believe you can start with $||A||_p$ the p norm and take the limit as $p\to\infty$ to prove the problem.
Isn't the infinity norm just the max of $|a_i|$ not the sum of them?
for a vector it is the max of $|a_i|$
 
Amer said:
Prove that for

$A \in \mathbb{R}^{n\times n} $
||A||_{\infty} = \text{max}_{i=1,...,n} \sum_{j=1}^n |a_{ij} |

I know that
$||A||_{\infty} = \text{max} \dfrac{||Ax||_{\infty} }{||x||_{\infty}} $

such that $x \in \mathbb{R}^n$

any hints
You might find it easier to use the equivalent definition $\|A\|_\infty = \max \{\|Ax\|_\infty : \|x\|_\infty \leqslant 1\}.$ For $\|x\|_\infty \leqslant 1$, show that $$\|Ax\|_\infty = \max_{1\leqslant i\leqslant n}|(Ax)_i| = \max_{1\leqslant i\leqslant n}\Bigl| \sum_{j=1}^n a_{ij}x_j \Bigr| \leqslant \sum_{j=1}^n |a_{ij} |.$$
For the reverse inequality, find $\|Ax\|$ where $x$ is the vector with a 1 in the $i$th coordinate and 0 for every other coordinate.
 

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