What is the Meaning of Cylindrical Vectors in Relation to Cartesian Vectors?

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salman213
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1. IM very confused about the meaning of these cylindrical vectors

for Cartesian vectors if i say A = 1ax + 2ay + 3az

I know i mean a vector with a magntiude of 1 in the x direction 2 in the y direction and 3 in the z direction and i make a line from the origin to point (1,2,3).

Now for cylindrical I cannot think the same way

for a point i can make a point easily it seems to have a similar meaning (r is the magntiude from origin to the point, phi being the angle from x and z being the regular z)


now for a vector example a = 1 ap + 2 aphi + 3 az


Im very confused how do i draw this vector and what does it mean?



the magntiude along p is 1 so the angle is 2? from the x axis?

i don't think this is correct.. I can't understand this help!


 
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Cylindrical coordinates can be thought of as a right triangle with a point of rotation at the origin. The one leg of the triangle lies in the x-y plane and is

[tex]\rho[/tex]

and the vertical leg is

[tex]\mbox{z}[/tex]

and the angle with respect to an axis, usually the x axis, that the triangle is rotated from is

[tex]\phi[/tex]

These three values form another orthogonal coordinate system but it is not fixed like a Cartesian coordinate system but changes direction as the point changes position.
 
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so you would not be able to draw the vector out?

how would i draw or specifiy a change in aphi like on a 3d plane what would the difference of

1 ap + 2aphi + 3az and 1 ap + 3aphi + 3az ?
 
the thing is this all seems to be about points i don't understand how to relate it to vectors in cylindrical system

I was wondering if someone can give me an idea of how to represent a vector in cylindrical coordinate system.

like on a 3d plane what would the difference of

1 ap + 2aphi + 3az and 1 ap + 3aphi + 3az ?
 
I think what you are looking for is a relation between the Cartesian vectors and the Cylindrical vectors. So, using the picture from the link given previously and some trigonometry, we have

[tex]\vec{x}=\rho\mbox{cos\phi}\hat{x}[/tex]

[tex]\vec{y}=\rho\mbox{sin\phi}\hat{y}[/tex]

[tex]\vec{z}=z\hat{z}[/tex]

where

[tex]\hat{x},\hat{y}, and \ \hat{z}[/tex]

are unit vectors in the x, y, and z directions. The inverse relations are

[tex]\vec{\rho}=\sqrt{x^2+y^2}\hat{\rho}[/tex]

[tex]\vec{\phi}=\arctan{\frac{y}{x}}\hat{\phi}[/tex]

The z value is the same for both coordinate systems. Hope this helps.