Conversion vectors in cylindrical to cartesian coordinates

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Homework Help Overview

The discussion revolves around converting a vector expressed in cylindrical coordinates to Cartesian coordinates, specifically focusing on the components of the vector and their relationships. The original poster presents a vector in cylindrical form and attempts to derive the x-component in Cartesian coordinates.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the transformation of cylindrical unit vectors into Cartesian coordinates, questioning the necessity of considering both the radial and angular components for accurate representation in Cartesian form.

Discussion Status

Participants are actively discussing the components needed to express the vector correctly, with some clarifying the roles of different components in the transformation process. There is recognition of the need to account for both the radial and angular contributions to the x-component.

Contextual Notes

Some participants express confusion regarding the completeness of the approach when only considering the radial component for the x-direction, indicating a need for further exploration of the angular component's contribution.

ForTheGreater
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Homework Statement


It's just an example in the textbook. A vector in cylindrical coordinates.
A=arAr+aΦAΦ+azAz
to be expressed in cartesian coordinates.
Start with the Ax component:
Ax=A⋅ax=Arar⋅ax+AΦaΦ⋅ax

ar⋅ax=cosΦ
aΦ⋅ax=-sinΦ

Ax=ArcosΦ - AΦsinΦ

Looking at a figure of the unit vectors I get it. At the same time I just don't understand why ArcosΦ isn't enough to get the magnitude of the Ax component.
 
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Because unit vector ##\hat{x}## has two components, one in the ##\hat{r}## direction and one in the ##\hat{\phi}## direction both of which depend on the angle ##\phi##. So when you express ##\hat{x}## as in ##A_x\hat{x}##, in terms of cylindrical unit vectors, you get two components which means you need the Pythagorean theorem to find the magnitude of ##A_x##.
 
If I have a point r=4, phi=pi/8 and z=z; in cylindrical coordinates.
sqrt( (r*cos(phi) )2 + (r*sin(phi) )2 ) = 4
So taking r*cos(phi) as the x component and r*sin(phi) as the y component seems to be enough to get the same point represented in both coordinate systems? What am I missing?
 
Suppose I gave you vector
$$\vec{A}=3\hat{a}_r-2 \hat{a}_{\phi}+4 \hat{z}$$
How would you proceed to find the Cartesian x-component of this vector? You will need the equations that transform the cylindrical unit vectors into the Cartesian unit vectors.
 
ForTheGreater said:

Homework Statement


It's just an example in the textbook. A vector in cylindrical coordinates.
A=arAr+aΦAΦ+azAz
to be expressed in cartesian coordinates.
Start with the Ax component:
Ax=A⋅ax=Arar⋅ax+AΦaΦ⋅ax

ar⋅ax=cosΦ
aΦ⋅ax=-sinΦ

Ax=ArcosΦ - AΦsinΦ

Looking at a figure of the unit vectors I get it. At the same time I just don't understand why ArcosΦ isn't enough to get the magnitude of the Ax component.
You did this correctly. In terms of interpretation, ##A_r \cos {\phi}## is only the component of the r component of A in the x direction. You also need the component of the ##\phi## component of A in the x direction. This is your ##-A_{\phi}s\sin{\phi}##
 
Thank you, I think I just didn't think of that you'll need both the Ax component and the Ay component of the vector to get the x coordinate.
 
ForTheGreater said:
Thank you, I think I just didn't think of that you'll need both the Ax component and the Ay component of the vector to get the x coordinate.
I think you meant Ar and Atheta
 

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