The concept of the
integral
[tex]\int_a^bY(x)dx[/tex]
of a map Y between two points
a and
b is much simpler: it is simply a measure of the signed area enclosed between the graph of Y and the x axis. (Where "signed area" means that the part of the erea where Y is <0 is
substracted from the part where Y>0.)
The idea is that we know the formula for the area of a rectangle (width times height) so we approximate the signed area enclosed between the graph of Y and the x-axis by the area of a couple rectangles. See the pictures here:
http://en.wikipedia.org/wiki/Integral.
Then we agree that as the number of rectangles increase, the sum of the signed areas of the rectangles approximates better and better the signed area enclosed between the graph of Y and the x-axis and so we define [itex]\int_a^bY(x)dx[/tex] as the sum of the signed areas of an infinite number of rectangles.<br />
<br />
Although the integral is simpler conceptually, the rigourous construction of it is as involved, if not more, as that of the derivative.<br />
<br />
<br />
Then there is the <b>fundamental theorem of differential and integral calculus</b> (FTC) which establises a link between the concept of derivative and that of integral. It says simply that<br />
<br />
[tex]\int_a^bY'(x)dx=Y(b)-Y(a)[/tex]<br />
<br />
It is useful because derivatives are easy to calculate and integrals are hard to calculate. So for instance, if you're wondering how to integrate the function 2x*cos(x²), then having mastered the rules of differentiations, you will recognized after a bit of reflection that by the chain rule, this is just the derivative of sin(x²). So the FTC above allows you to write<br />
<br />
[tex]\int_a^b2x\cos(x^2)dx=\int_a^b\frac{d(\sin(x^2))}{dx}dx=\sin(b^2)-\sin(a^2)[/tex].<br />
<br />
Initially, one might not see the point of practicing using the rules of differentiation over and over like and automaton, but in fact, as a corollary of the preceeding little example, we see that it is <b>very </b>useful. For withouth that practice, I would not have realized that 2x*cos(x²)=d(sin(x²))/dx. The conceptual understanding of differentiation and integration allows you to <i>translate </i>a real word problem into a mathematical problem and a mastery of the rules of differentiation allow you to <i>solve </i>it.[/itex]