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Sarah88
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Homework Statement
A circuit employs a silicon solar cell to detect flashes of light lasting .25 seconds. The smallest current the circuit can detect reliably is .42 [tex]\mu[/tex]A. Assuming that all photons reaching the solar cell give their energy to a charge carrier, what is the minimum power of a flash of light of wavelength 550 nm that can be detected?
Homework Equations
E= h*f
f= c/wavelength
The Attempt at a Solution
I first found the energy by h*(c/wavelength) --> 6.63*10^-34 m^2 kg/s * (3*10^8 m/s)/(550*10^-9 m) = 3.62*10^-19 J. Since 1 W= 1 J/s, I took the energy and divided it by the time of .25 seconds (to get an answer of 1.45*10^-18 W). However, this answer is wrong, was I wrong in neglecting the current in the circuit? Does this end up changing the J of energy? I know P can equal I*V, or I^2*R, but I'm not sure how to incorporate power with current in this sort of problem. Thank you!