How many photons are produced when a 0.39 kg mass falls from a height of 2.9 m?

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SUMMARY

A 0.39 kg mass falling from a height of 2.9 m converts its gravitational potential energy into visible light photons. Using the equation E=hc/λ, where Planck’s constant is 6.63 × 10^−34 J·s and the speed of light is 3 × 10^8 m/s, the energy of a single photon at a wavelength of 5.5 × 10^−7 m is calculated to be approximately 3.618 × 10^−10 J. The total energy released during the fall, calculated using the formula x = 0.5at², results in a fall time of approximately 0.769 seconds. The discussion concludes that the number of photons produced can be determined by dividing the total energy by the energy per photon.

PREREQUISITES
  • Understanding of gravitational potential energy
  • Familiarity with Planck’s constant and photon energy calculations
  • Basic knowledge of kinematics, specifically the equations of motion
  • Concept of wavelength in relation to electromagnetic radiation
NEXT STEPS
  • Calculate the total energy released during the fall using gravitational potential energy formulas
  • Learn about photon energy calculations using E=hc/λ
  • Explore the relationship between energy and wavelength in electromagnetic radiation
  • Investigate the implications of energy conversion in physical systems
USEFUL FOR

Students in physics, educators teaching energy conversion concepts, and anyone interested in the relationship between mass, energy, and light production.

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Homework Statement


A 0.39 kg mass falls from a height of 2.9 m. If all of the energy of this mass could be converted to visible light of wavelength 5.5 × 10^−7 m, how many photons would be produced? The acceleration of gravity is 9.8 m/s^2 . Planck’s constant is 6.63 × 10^−34 J · s, and the speed of light is 3 × 10^8 m/s.

Homework Equations


E=hc/λ
p=h/λ
x=.5at^2

The Attempt at a Solution


E=hc/λ=(1.99x10^-25)/(5.5x10^-7)=3.618x10^-10J
x=.5at^2 > 2.9=.5(9.8)t^2 > t=.769s

I think I need to find power but have looked everywhere online and we do not have textbooks to find it with the given data.
 
Physics news on Phys.org
You don't need to find power. You could find it if you neglect air resistance but you don't need it.
You know the energy of a single photon.
You know the energy released in falling.
 

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