SUMMARY
A 0.39 kg mass falling from a height of 2.9 m converts its gravitational potential energy into visible light photons. Using the equation E=hc/λ, where Planck’s constant is 6.63 × 10^−34 J·s and the speed of light is 3 × 10^8 m/s, the energy of a single photon at a wavelength of 5.5 × 10^−7 m is calculated to be approximately 3.618 × 10^−10 J. The total energy released during the fall, calculated using the formula x = 0.5at², results in a fall time of approximately 0.769 seconds. The discussion concludes that the number of photons produced can be determined by dividing the total energy by the energy per photon.
PREREQUISITES
- Understanding of gravitational potential energy
- Familiarity with Planck’s constant and photon energy calculations
- Basic knowledge of kinematics, specifically the equations of motion
- Concept of wavelength in relation to electromagnetic radiation
NEXT STEPS
- Calculate the total energy released during the fall using gravitational potential energy formulas
- Learn about photon energy calculations using E=hc/λ
- Explore the relationship between energy and wavelength in electromagnetic radiation
- Investigate the implications of energy conversion in physical systems
USEFUL FOR
Students in physics, educators teaching energy conversion concepts, and anyone interested in the relationship between mass, energy, and light production.