What is the minimum force T necessary to lift the wheel?

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Discussion Overview

The discussion revolves around determining the minimum torque T required to lift a retracting nose wheel assembly, focusing on the mechanics involved in the application of torque through a linkage system. Participants explore the relationship between forces, moments, and the geometry of the system, with an emphasis on the calculations necessary to solve the problem.

Discussion Character

  • Homework-related
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant describes the problem and seeks assistance in calculating the necessary torque T to lift the wheel assembly.
  • Another participant explains that the torque must be sufficient to counteract the moment created by the combined mass of the wheel and arm, which is given as 50 kg.
  • A participant mentions calculating the moment between points A and G as 245 Nm but expresses uncertainty about its relation to points B and C.
  • Further clarification is provided regarding the calculation of the lifting moment, indicating that it must be equal to or greater than the opposing moment for the wheel to lift.
  • There is a discussion about the forces acting at points D and C, and how the torque T is applied along the linkage BD.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the relationship between the calculated moments and the forces at play, indicating that multiple viewpoints and uncertainties remain in the discussion.

Contextual Notes

Participants reference specific angles and forces but do not fully resolve the mathematical relationships or assumptions necessary for a complete solution.

grayworks
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Hi I'm very new so I'm not sure if this is the best place to put this in. I've got a problem that I'm having trouble working out and any help would be great.

'A retracting nose wheel assembly is raised by the application of a torque T applied to link BC through a shaft at B. The wheel and arm AO have a combined mass of 50kg with a centre of mass at G. Find the value of T necessary to lift the wheel when D is directly under B at which position angle is 30degrees.

Cheers
 

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The torque acts on a moment arm, and one must determine the necessary force at D (normal) the arm AO.

So the force/moment is applied at D, but that moment must be at least equal to the moment of wheel and arm AO. That information is given - "a combined mass of 50kg with a centre of mass at G."

This post belongs in the Engineering and Technology Homework Forum.
 
k I've worked out the moment between A-G is 245Nm but I can't see how this relates to B-C
 
grayworks said:
k I've worked out the moment between A-G is 245Nm but I can't see how this relates to B-C
One needs to show work. It would appear that one use 50 kg * 9.8 m/s2 * cos (60°), which is correct.

The applied moment must be in the opposite direction of that and of the same or greater magnitude for the wheel to move. The lifting moment operates at D perpendicular to AD, which has a moment arm 0.8 m.

Has one done moments/torques through linkages?

CD applies a force at D, and BC applies a force to CD.

The torque T, acts along BD, by virtue of BC and CD.
 

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