What Is the Minimum Height of a Rear-View Mirror to See the Entire Rear Window?

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Homework Help Overview

The problem involves determining the minimum height of a rear-view mirror needed for a driver to see the entire height of a rear window in a car. The dimensions of the rear window and the distances from the driver's eyes to the mirror and the window are provided.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various attempts to apply formulas related to similar triangles and ratios to solve the problem. Some express uncertainty about the correctness of their equations and seek clarification on the underlying principles.

Discussion Status

There is an ongoing exploration of different methods to approach the problem, with some participants suggesting the use of diagrams to clarify relationships. A few have reported success with their attempts, while others continue to question the validity of their approaches.

Contextual Notes

Participants mention the importance of understanding the principles of reflection and geometry in solving the problem. There is a suggestion to consider a simpler related problem to build understanding before tackling the main question.

sweetgirl86
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I have been trying to solve this problem using many equations, but am not getting the right answer. I guess I'm not using the right formula because I don't know it. Can someone please help.

The rear window in a car is approximately a rectangle, 1.17 m wide and 0.160 m high. The inside rear-view mirror is 0.600 m from the driver's eyes, and 1.23 m from the rear window. What is the minimum height of the rear-view mirror if the driver is to be able to see the entire height of the rear window in the mirror without moving her head?
do: 1.23m
di: 0.600m
ho: 0.160m
hi: ?

hi = (di/do)ho = (0.600/1.23)0.160m = 0.0780m
 
Last edited:
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This is how i tried to solve it:

do: 1.23m
di: 0.600m
ho: 0.160m
hi: ?

hi = (di/do)ho = (0.600/1.23)0.160m = 0.0780m
 
This sounds like triangles and simple ratios, sweetgirl. Unfold the reflection, then you've got a triangle .6m long within a triangle 1.23m + .6m long. Do you know if the first answer is

.16 x .6 / 1.83 = .05245
 
sweetgirl86 said:
This is how i tried to solve it:

do: 1.23m
di: 0.600m
ho: 0.160m
hi: ?

hi = (di/do)ho = (0.600/1.23)0.160m = 0.0780m
Where does this equation come from? It is wrong.

If you draw a diagram and identify the correct similar triangles, you will get the correct formula.

Physics is not about trying different formulas and hoping one of them works. It is about arriving at the correct formula by a combination of math and a knowledge of the fundamental principles.

In this case, since the rear-view mirror must be assumed to be planar, the principle that is relevant is the relationship between the angle of incidence and reflection. From there, it's just a geomtry problem.

Can you draw a diagram, label the various points and find the relationship from there? Have you come across the simpler problem where you are asked to find out how tall a mirror you need to completely view yourself? If not, it might be instructive to first attempt this simpler problem before going on to the one you have.
 
Last edited:
Thank You so much. I tried solving it the triangle way and go the right answer. And yes that's the right answer farsight. Thank you all so much. I solved the second part by myself :-).
 

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