Light reflections in concave/convex mirrors

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SUMMARY

The discussion revolves around the physics of light reflections in concave and convex mirrors, specifically analyzing a hubcap that acts as a spherical mirror. The man observes two images of his face at distances of 30 cm and 10 cm behind the hubcap. Using the mirror formula (1/Di + 1/Do = 1/f) and magnification formula (M = -Di/Do), participants conclude that the object distance (Do) can be determined by solving the equations for both cases. The images are identified as virtual and upright due to their positions relative to the mirror.

PREREQUISITES
  • Understanding of mirror equations: 1/Di + 1/Do = 1/f
  • Knowledge of magnification calculations: M = Hi/Ho = -Di/Do
  • Familiarity with the concepts of real and virtual images
  • Basic principles of optics, particularly spherical mirrors
NEXT STEPS
  • Study the derivation of the mirror formula and its applications
  • Explore the differences between concave and convex mirrors in detail
  • Learn about the significance of focal length in mirror optics
  • Investigate practical applications of spherical mirrors in everyday life
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Students studying optics, physics educators, and anyone interested in understanding the behavior of light in concave and convex mirrors.

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Homework Statement



A man polishes the insided and outside of a hubcap that is a section of a sphere. When he looks into one side of the hubcap, he sees an image of his face 30cm behind the hubcap. He then turns the hubcap over and sees another image of his face 10 cm behind the hubcap.
a)How far is his face from the hubcap?
b)What is the radius of curvature of the hubcap?
c)What is the magnification for each image?
d)Are the images real or virtual?
e)Are the images upright or inverted?


Homework Equations



1/Di + 1/Do = 1/f Di= distance of image Do=distance of object f= focal point

M= Hi/Ho = -Di/Do M= magnification Hi= height of image Ho= height of object


The Attempt at a Solution



a) i believe you have to use the first equation but i am unsure of how to use the given data in it, could you possibly do... 1/-30 + 1/-10 + 2/Di = 2/f ?

b)find the focal point and double it i believe

c)use M= -Di/Do for both but i don't know the Do from part "a"

d)virtual because the image is behind the mirror

e)upright because all virtual images are upright?

-- i think i am on the right track, but not sure--
 
Physics news on Phys.org
Keeping Do same, write two equation for two cases. Since R is the same fore both the case, f is the same, but sign will change. From these equation you can find Do. Once you find Do, other thing are easy.
 

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