MHB What is the Minimum Number of Friends Needed for Unique Dinner Invitations?

Click For Summary
To determine the minimum number of friends John needs for unique dinner invitations, the correct approach is to set the inequality as \(\binom{n}{3} \geq 365\). This leads to the equation \(\frac{(n-1)(n-2)n}{6} \geq 365\). The solution requires finding the smallest natural number \(n\) that satisfies this inequality. It is noted that \(\binom{14}{3} = 364\), indicating that at least 14 friends are necessary. Thus, John needs a minimum of 14 friends to ensure he can invite different triplets each evening without repetition.
Lancelot1
Messages
26
Reaction score
0
Hello all,

I am trying to solve this one:

John has n friends . He wants to invite in each evening (365 days a year) three of his friends for dinner. What should be the size of n, such that it will be possible not to invite the same triplet twice ?

What I did was:

\[\binom{n}{3}\leq 365\]

which turns into:

\[\frac{(n-1)(n-2)n}{6}\leq 365\]

I have tried to solve it, manually and with a mathematical software, in both ways n was not a natural number...where is my mistake ?
 
Mathematics news on Phys.org
Lancelot said:
I have tried to solve it, manually and with a mathematical software, in both ways n was not a natural number
First, the inequality should be $\binom{n}{3}\ge365$. Second, the answer to this problem is an inequality $n\ge\ldots$, not a specific value of $n$. For the lower bound of $n$ take the smallest natural number that is equal to or larger than the root of that equation. Note that $\binom{14}{3}=364$.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 5 ·
Replies
5
Views
4K