What Is the Minimum Power Output for a 68.8kg Athlete Climbing 4.74m in 8.70s?

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Homework Help Overview

The problem involves calculating the minimum power output of a 68.8kg athlete climbing a vertical distance of 4.74m in 8.70s, focusing on the concepts of work and power in a physics context.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula for average power and the calculations involved, questioning the correctness of the initial answer and considering the impact of rounding and the value of gravitational acceleration used.

Discussion Status

Some participants have provided calculations and suggested that rounding may be an issue, while others are questioning the approach taken to solve the problem. There is no explicit consensus on the correctness of the method used.

Contextual Notes

Participants note that the problem specifies a minimum power output, which may imply additional considerations in the calculations. There is also mention of an online course format where answers are validated for correctness.

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1. In the rope climb, a 68.8kg athlete climbs a vertical distance of 4.74m in 8.70s. What minimum power output was used to accomplish this feat?



2. Average Power = Work / time



3. P = mgh/t = 367 W, which is apparently the wrong answer (this is an online course where you input the answer and they tell you if it's correct). I also tried -367W but that doesn't work either. Perhaps this has something to do with the problem asking for minimum power output? Could someone help me out?
 
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If you use g=9.81 the answer should round to 368 W
 
But is this the right way to do this problem?
 
opqpop said:
But is this the right way to do this problem?

Yes. It's probably a rounding problem as kamerling pointed out.
 

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